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#1 2012-07-16 07:27:34

marcalcc
Member
Registered: 2011-03-26
Posts: 15

360*180 panoramas

Hi all,

I was wondering if there is a way to actually calculate how many rows and how many pictures per row are necessary to shot these 360*180 panoramas.

I´ve an Excel file where by adding the sensor size and focal length of the gear, you can calculate how many shots per row you need for "normal panoramas", but 360*180 are different as you need less photos/row as you go up to the zennit/nadir points.

The reason I´m asing is that I want to update an app I wrote for iOS (Pano Assist) but I have no first-hand experience on thes 360*180, so I have to get this experience before anything else.

Any help would be much appreciated! Thanks in advance!

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#2 2012-07-16 10:06:16

mediavets
Moderator
From: Isleham, Cambridgeshire, UK.
Registered: 2007-11-14
Posts: 9731
Website

Re: 360*180 panoramas

This Papyspheric Python script will genaret a set of shooting co-ordinates optimised for shooting spheriocal panos:

http://www.kolor.com/forum/t8100-papysp … es?id=8100


Andrew Stephens
Nikon D40, Nikkor 10.5mm fisheye, Sigma 8mm f3.5 fisheye, Nikkor 18-55/50/35mm lenses, Nodal Ninja 5 Lite, Nodal Ninja 4 with R-D16, Agno's MrotatorTCS short.
Nikon P5100, CP5000, CP995, FC-E8, WC-E63,WC-E68, TC-E2, Kaidan Kiwi 995, Bophoto pano bracket, Agno's MrotatorA.
Merlin/Orion robotic pano head + Papywizard on Nokia 770/N800/N810 and Windows 8/XP/2K.

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#3 2012-07-16 10:29:45

HansKeesom
Member
Registered: 2010-07-19
Posts: 1422
Website

Re: 360*180 panoramas

marcalcc wrote:

Hi all,

I was wondering if there is a way to actually calculate how many rows and how many pictures per row are necessary to shot these 360*180 panoramas.

I´ve an Excel file where by adding the sensor size and focal length of the gear, you can calculate how many shots per row you need for "normal panoramas", but 360*180 are different as you need less photos/row as you go up to the zennit/nadir points.

The reason I´m asing is that I want to update an app I wrote for iOS (Pano Assist) but I have no first-hand experience on thes 360*180, so I have to get this experience before anything else.

Any help would be much appreciated! Thanks in advance!

my thumbrule is 600 : #mm of lens. So with 10 mm lens I rotate at 60: 10 = 60 degrees. Now that is horizontal rotation with portrait position. Vertically you have 180 to cover but instead of 60 you can use 90 degrees because of 2:3 relation. So then I choose + 45 and -45 position to start with, but because -45 is taking part of tripod legs I will change into +50 degrees and -10 degrees and do a number of nadir shots from different direction.

Same thing will work for other mm of lens. for example 24 mm lens   600 : 24 = 25 degrees horizontally and 35 degrees vertically roughly.

but yes, there are calculators for it.


Regards,  Hans Keesom
I stitch and render for other photographers see http://tinyurl.com/brxvlhg for details

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